Index:The Book of Statistical ProofsGeneral TheoremsProbability theoryVariance ▷ Variance of a sum

Theorem: The variance of the sum of two random variables equals the sum of the variances of those random variables, plus two times their covariance:

V a r (X + Y) = V a r (X) + V a r (Y) + 2 C o v (X,Y).(1)

Proof: The variance is defined in terms of the expected value as

V a r (X) = E [(X − E (X)) 2].(2)

Using the linearity of the expected value and the definition of the covariance, we can derive (1) as follows:

V a r (X + Y) (2) = E [((X + Y) − E (X + Y)) 2] = E [([X − E (X)] + [Y − E (Y)]) 2] = E [(X − E (X)) 2 + (Y − E (Y)) 2 + 2 (X − E (X)) (Y − E (Y))] = E [(X − E (X)) 2] + E [(Y − E (Y)) 2] + E [2 (X − E (X)) (Y − E (Y))] (2) = V a r (X) + V a r (Y) + 2 C o v (X,Y).(3)

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Metadata: ID: P128 | shortcut: var-sum | author: JoramSoch | date: 2020-07-07, 06:10.